BASIC TRIGONOMETRY QUESTIONS FOR SSC

These questioins are for those who were either not so good in the secondary classess maths or who are not in touch with the following concepts from 4-5.
As I said these questions are Basic . But some questions are asked by ssc in previous years examination.

Question 1-
Express the following angles in radian measure and centesimal measure :
a]45°       
b]20°35'      
c] 50°38'40"

Solutions:-
the term ["] is called as seconds & the term ['] is called as minute 

So, we need to do is that term second should be in minute & the term minute should be in hour (because ° is counted in hour)

solution - 1] a.
as we know 180°= π radian.
 1 degree is equal to = π/180
         45°ℝℙ= 45*π/180= π/4

solution 1]b. 
    35' = 35/60 hour now, 20+35/60= 247/12 degree
         now change in radian 247/12*π/180= 1235/54 grad.

solution 1]c. 
40"=40/60minutes now 38+40/60=116/3min.
  after converting minutes in hours 116/180 , add all now 50+116/180=2279/45 degree , Now change it to radian , 2279/45*π/180=2279/7290




Question - 2 
One angle of a triangle is 54 degree and another is π/4 radian. Find the third angle in centesimal unit i.e. degree

Solution no-2
angle A=54, angle B= π/4rad. 
                  angle B=45degree

total measures of a triangle is 180 degree so to get remaining i.e. third angle We subsctract the sum of Both from 180 degree Ans. 180- 99= 81 degree

Value of 1 rad=57°16'22"
Question no-3 
Find the values of 
a)sin2295°
b)tan 1500°
c)tan405°
d)sin225°

Solutions.........
a) sin2295°= sin(6*360° +135°)    { easy way to get this is to divide by 360° i.e. 2295/360°}
as last day On 27 apr., 2017 i have explained in my post in the first quadrants all the trignometric identities are postive, 
Note:- we only take which is left i.e. 135°
sin(135°)= sin (180-45)= sin 45° Ans.......

b.) tan1500°=tan (4*360°+60°)
     tan60°
Now you are able to solve c,d of it.

SOME OF THE SSC'S MOST IMPORTANT PREVIOIUS YEARS IDENTITIES.

QUESTION NO- 4
find the value of 
Sin(22½)=?
Let θ= 22+1/2 
2θ=45
take Cos both the sides
i.e. Cos2θ=cos45
       1/√2=1-2sin²22½    {let sin 22½= X)
now 2x²=1-1/√2
 by soving it we get the value , 

if there were cos instead of sin we can change the sign i.e. "+"

Question no- 5 
Find the value of 
sin15
sin75
hints 15 can be written as 45-30
and 75 can be written as 45+30



SO friends thease are the basic question on trigonometry which is being asked in ssc directly of indirectly. trigonometry is vast it can not be done in a day. 
THANK YOU KEEP VISITING KEEP LEARNING AFTER THAT TEACH YOUR EXPERIENCE TO THE ONE WHO'S NEEDY OF IT.